# SOLUTION: i hope you can solve the following for me: 1. x2m+n (2m+n being the exponent) ------ xm+3n (m+3n being the exponent) 2. 22m+2 (2m+2 being the exponent)

Algebra ->  Algebra  -> Exponents -> SOLUTION: i hope you can solve the following for me: 1. x2m+n (2m+n being the exponent) ------ xm+3n (m+3n being the exponent) 2. 22m+2 (2m+2 being the exponent)       Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Exponents and operations on exponents Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponents Question 441213: i hope you can solve the following for me: 1. x2m+n (2m+n being the exponent) ------ xm+3n (m+3n being the exponent) 2. 22m+2 (2m+2 being the exponent) ----- 2(2m-1)2 ( (2m-1)2 being the exponent) 3. (x+1)3n-2 (3n-2 being the exponent) --------- (x+1)2-3n (2-3n being the exponent) THANK YOUAnswer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, Note the use of ^ (uppercase 6) Refer to the Laws governing exponents: ** **** 1. 2. 3. ```