SOLUTION: Can you tell me if I have simplified this equation correctly? (9y^2/(x^-8*y^0))^1/2 I first found that y^0 = 1. So that would drop out of the equation. Then I thought that

Question 43526: Can you tell me if I have simplified this equation correctly?
(9y^2/(x^-8*y^0))^1/2
I first found that y^0 = 1. So that would drop out of the equation.
Then I thought that raising to the 1/2 is the same as taking the square root of the equation.
So I now have the square root of 9y^2 / square root of x^-8.
The square root of 9y^2 is 3y. So I now have 3y/square root of x^-8.
I think that a negative exponent is the reciprocal of the positive so I now have 3y * square root of x^8. And x^8 is x^4 * x^4. So if I take the square root of x^4 is x^2. So I ended up with 3y*2x^2. Is that right?

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let's see...you want to simplify:

Your first step is correct:, so now yu have:

Your second statement is also correct:.
So now you want to multiply the internal exponents by the external exponent:
Simplify this. For the numerator: = 3 and = y
And for the denominator:
Now bring the denominator up and change the sign of the exponent.

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