SOLUTION: (3500)*(1.08)^X=14000*(1.03)^X
can you please explain how to solve it? Thanks!
Algebra.Com
Question 430427: (3500)*(1.08)^X=14000*(1.03)^X
can you please explain how to solve it? Thanks!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
(3500)*(1.08)^X=14000*(1.03)^X
..
(1.08)^x/(1.03)^x=14000/3500=4
(1.08/1.03)^x=4
take logs of both sides
xlog(1.08/1.03)=log4
x(log1.08-log1.03)=log4
x=log4/(log1.08-log1.03)=29.2453..
RELATED QUESTIONS
Hi. Can you please explain to me how to work out decimal numbers. Im trying to learn for... (answered by mananth)
Assume being overweight is a function of how many calories are consumed weekly. Let x... (answered by stanbon)
-1/4(x-8)+1/2(x+2)=x+9
Could someone help to explain how to solve this?
I seem to... (answered by scott8148,rfer)
Can you please solve the Integral and explain how you did it
Integral of {{{... (answered by ikleyn)
can you please explain how to solve this?
x/6 + 3x/7 = 25
Please and... (answered by Earlsdon)
I am trying to help my son with his algebra homework but never really understood it... (answered by rapaljer)
x-2 = 7 + 3
Please explain how to solve this problem. It is only 1 problem. (answered by richwmiller)
please help me solve the equation: {{{x=i^(1/3)}}} also could you explain how to solve... (answered by stanbon)
log5(x+135)+log5(x+11)=3
Can you please explain how to solve for x for this equation?
(answered by josgarithmetic)