SOLUTION: How would I find integers m and n such that {{{(2^m)(5^n)=0.0032}}}.

SOLUTION: How would I find integers m and n such that {{{(2^m)(5^n)=0.0032}}}.

Algebra.Com

Question 411829: How would I find integers m and n such that .
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
.0032 = 32 * 10^(-4) = 2^5 * (2 * 5)^(-4) = (2^1) * [5^(-4)]
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