SOLUTION: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!!

Question 394614: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I need the last two digits from the following numbers 11^2011.
-------------------
The last 2 digits are cyclic, and are equal to the exponent modulo 10.
For exponents from 1 to 10, they are:
11
21
31
41
51
61
71
81
91
01
Then they repeat.
2011/10 = 201 remainder 1, so the last 2 digits are the same as 11^1
= 11.

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