SOLUTION: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b. 5^x = 32 x=

Question 363573: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x = 32
x=
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x = 32
if 2^a = 5, then log2 5 = a, log2 5 = (log10 5)/(log10 2) = a
a = 2.3219 rounded to 4 places
if 2^b = 9, then log2 9 = b, log2 9 = (log10 9)/(log10 2) = b
b = 3.1699 rounded to 4 places
if 5^x = 32, then log5 32 = x, log5 32 = (log10 32)/(log10 5) = x
x = 2.1534 rounded to 4 places
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