# SOLUTION: 99-6^2/4^2-3^2

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 Algebra: Exponents and operations on exponents Solvers Lessons Answers archive Quiz In Depth

 Question 343251: 99-6^2/4^2-3^2Answer by haileytucki(390)   (Show Source): You can put this solution on YOUR website!99-(6^(2))/(4^(2))-3^(2) Squaring a number is the same as multiplying the number by itself (6*6). In this case, 6 squared is 36. 99-(36)/(4^(2))-3^(2) Squaring a number is the same as multiplying the number by itself (4*4). In this case, 4 squared is 16. 99--(36)/(16)-3^(2) Squaring a number is the same as multiplying the number by itself (3*3). In this case, 3 squared is 9. 99--(36)/(16)-9 Subtract from 99 to get 98. 98-(36)/(16)-9 Subtract 9 from 98 to get 89. 89-(36)/(16) To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 16. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 89*(16)/(16)-(36)/(16) Complete the multiplication to produce a denominator of 16 in each expression. (1424)/(16)-(36)/(16) Combine the numerators of all fractions that have common denominators. (1424-36)/(16) Subtract 36 from 1424 to get 1388. (1388)/(16) Reduce the expression (1388)/(16) by removing a factor of 4 from the numerator and denominator. (347)/(4)