SOLUTION: How do you figure a negative exponet in the fowolling equation.
(m^-2 n^3 p^4)^-2 (mn^-2 p^3)^4
___________ ___________ _________
(mn^-2 p^3)^-4 (mn^2 p)^-1
there are
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Question 334851: How do you figure a negative exponet in the fowolling equation.
(m^-2 n^3 p^4)^-2 (mn^-2 p^3)^4
_________________________________
(mn^-2 p^3)^-4 (mn^2 p)^-1
there are the negative exponets outside the () and I am not sure how to 'get rid of' the negative.
thanks for the help.
Found 2 solutions by vleith, solver91311:
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Power to a power rule say 'multiply them'.
So do that first.
Then move the remaining 'negative' powers and make them postives (if negative is in the numerator, move to the denominatopor and change the sign or vice-versa)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use the fact that 
Use the fact that ^m\ = x^{mn})
Use the fact that 
Rid yourself of parentheses first:
^{-2} (mn^{-2} p^3)^4}{(mn^{-2} p^3)^{-4} (mn^2 p)^{-1} })
 (mn^{-8} p^{12})}{(mn^{8} p^{-12}) (mn^{-2} p^{-1}) })
Now move negative exponents from denominator to numerator or vice versa to get rid of the negative signs:
John
My calculator said it, I believe it, that settles it
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