SOLUTION: 64x3 +27
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Algebra: Exponents and operations on exponents
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Question 32858
:
64x3 +27
Found 2 solutions by
mukhopadhyay, Prithwis
:
Answer by
mukhopadhyay(490)
(
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put this solution on YOUR website!
64x^3 + 27
= (4x)^3 + 3^3
= (4x+3)[(4x)^2 - (4x)(3) + 3^2)]
= (4x+3)(16x^2 - 12x + 9)
Answer by
Prithwis(166)
(
Show Source
):
You can
put this solution on YOUR website!
64x^3 + 27
= (4x)^3 + 3^3
= (4x+3)[(4x)^2 - (4x)(3) + 3^2)]
= (4x+3)(16x^2 - 12x + 9) And there is your answer