SOLUTION: solving an equation with exponent using the even root property, where y is a real number. (y+6)^2-75=0

Question 326574: solving an equation with exponent using the even root property, where y is a real number.
(y+6)^2-75=0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Add to both sides.

Combine like terms.

Take the square root of both sides.

or Break up the "plus/minus" to form two equations.

or Simplify the square root.

or Subtract from both sides.

--------------------------------------

Answer:

So the solutions are or .

RELATED QUESTIONS
can you help with this problem I really don't understand it and how to solve it... (answered by Edwin McCravy)

(y+6)^2-75=0 solving an equation with exponent using the even root... (answered by stanbon)

Which of the following relations is NOT a function? (2.0 points) A) an ascending line... (answered by Fombitz)

Solve using the square root property, assuming 2 is an exponent: (x - 7 ) 2 =... (answered by stanbon)

Roots A.)Find each root - sq root 25 B) Quotient Rule for Radicals Simplify... (answered by solver91311)

if y is any real number, the y exponent 1= (answered by solver91311)

Show that the number(square root of 2 with exponent of square root of 2)with exponent of... (answered by jim_thompson5910)

Where does the line (x; y; z) = (4; 2; 1) + t(-2;-1; 0), (t is an element of the Real... (answered by Fombitz)

Solve the equation by using the square root property. Express the radical in simplest... (answered by Alan3354)