SOLUTION: Find the quotient using long division: (6x^2 -9x +4)/(x-2)

Question 286493: Find the quotient using long division:
(6x^2 -9x +4)/(x-2)
Answer by texttutoring(324) (Show Source): You can put this solution on YOUR website!
I don't know how to write a long division statement on here, so I will try my best to explain.
Go through it step by step:
How many times does x go into 6x^2? Or in other words, what is 6x^2 / x ?
it is 6x. Write 6x above the line, on top of the 9x.
Multiply 6x*x, subtract from 6x^2 to get 0.
Multiply 6x(-2) to get -12x.
Subtract -12x from -9x to get +3x (subtract a negative number is the same as adding)
Now divide 3x by x. You should get 3. Write this number after the 6x, above the line. It should say 6x + 3 now.
Multiply 3 by x to get 3x, subtract from 3x to get 0.
Multiply 3 by -2 to get -6, subtract from 4 to get 10.
The answer is 6x+3, Remainder=10
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