SOLUTION: i don't remember how to do this: (2^-3*x^-4*y^-3)/ (x^3*y^-2)^-1 i am supposed to write this with only positive exponents

SOLUTION: i don't remember how to do this: (2^-3x^-4y^-3)/ (x^3*y^-2)^-1 i am supposed to write this with only positive exponents

Question 257955: i don't remember how to do this:
(2^-3*x^-4*y^-3)/ (x^3*y^-2)^-1
i am supposed to write this with only positive exponents
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
A negative exponent means use the reciprocal.
In the case of x/y it becomes y/x
In the case of z It becomes 1/z
and in the case of 1/w it becomes w
Let's start with the numerator where every term has a negative exponent.

But we also notice that the entire denominator has a negative exponent.
So the fraction becomes:

But the y term in the numerator has a negative exponent.

We have dealt with all the negative exponents. Now to reduce and combine
2^3=8
x^3/x^4=1/x
y^2*y^3=y^5

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