SOLUTION: How do you solve:
(x^10*y^(-8))^-3
that is x to the exponent of 10; y to the exponent of -8; and all of it to the -3
Algebra.Com
Question 255642: How do you solve:
(x^10*y^(-8))^-3
that is x to the exponent of 10; y to the exponent of -8; and all of it to the -3
Found 3 solutions by stanbon, Alan3354, richwmiller:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You can't.
You don't have an equation.
And you have two variables.
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Cheers,
Stan H.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do you solve:
(x^10y^-8)^-3
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It's not an equation, so it can't be solved, only simplified.
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PS use ^ for exponents, above the 6.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Very interesting problem. Easy solution.
The important thing to remember is negative exponent means the reciprocal.
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We have reciprocals of reciprocals in your problem.
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so
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Let's deal with the reciprocal now
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