SOLUTION: Hello, Can someone help me with these, I have some of the graphs but I not able to post them to this screen, and the last two problem I stuck on them since yesterday. Please help

Question 249192: Hello,
Can someone help me with these, I have some of the graphs but I not able to post them to this screen, and the last two problem I stuck on them since yesterday. Please help me

1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Use the resulting pairs to plot the graph. State the equation of the line asymptotic to the graph. .
I have a graph but I not sure that it is right and it will not post to this screen.
2. evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Use the resulting ordered pairs to plot the graph. State the equation of the line asymptotic to the graph.
Again I have the graph but I not sure if it is right and I can not post it to this screen

3. solve; the number of dislocated impulses per cubic inch in a transformer increases when lightning strikes by D=1900(2)^x, where x is the time in milliseconds fo the lightning strike. Find the number of dislocated impulses at x=0 and x=4

4. how long will it take for the population of a certain country to triple if its annual growth rate is 2.8%?(round to the nearest year). Use the exponential growth model P(t)=P0e^kt
Thank you,
Tammy
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started.

# 1

In order to graph , we need to plot a few points.

To get points in the form of (x,y), we need to find corresponding 'y' values to given 'x' values.

Let's find the y value when note: you can start at any x value.

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (-3,3.008).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (-2,3.04).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (-1,3.2).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (1,8).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (2,28).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Raise 5 to the power of to get .

Add.

So if , then which gives us the point (3,128).

----------------------------

Now let's make a table of the values we just found.

Table of Values:

Now let's plot the points. Note: not all of the points will be visible.

Graph:

Now draw a curve through all of the points to graph :

Graph of

============================================================
# 2

In order to graph , we need to plot a few points.

To get points in the form of (x,y), we need to find corresponding 'y' values to given 'x' values.

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

Negate to get .

So if , then which gives us the point (0.25,0.861).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

Negate to get .

So if , then which gives us the point (0.5,0.431).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

Negate to get .

So if , then which gives us the point (0.75,0.179).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

So if , then which gives us the point (1,0).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

So if , then which gives us the point (2,-0.431).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

So if , then which gives us the point (3,-0.683).

----------------------------

Let's find the y value when

Start with the given equation.

Plug in .

Evaluate the log base 5 of to get .

So if , then which gives us the point (4,-0.861).

----------------------------

Now let's make a table of the values we just found.

Table of Values:



x y
0.25 0.861
0.5 0.431
0.75 0.179
1 0
2 -0.431
3 -0.683
4 -0.861

Now let's plot the points:

Graph:

Now draw a curve through all of the points to graph :

Graph of
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