SOLUTION: At noon, there were 1000 bacteria in a culture dish. The formula for the growth of the bacteria is n = l000(2a), where n is the number of bacteria, and a is the number of hours th

Question 24646: At noon, there were 1000 bacteria in a culture dish. The formula for the growth of the bacteria is n = l000(2a), where n is the number of bacteria, and a is the number of hours the culture has been growing. How many bacteria will there be at 18:00, assuming none of the culture die? a is an exponent.

Simplify
(k2lm2)(-kn)2 ..the 2's are exponents.

Answer by quentin252(19) (Show Source): You can put this solution on YOUR website!
okay, so n=1000*(2^a)
and at 18:00 hrs a=6 (since 18:00=6pm is 6 hrs past noon=12:00)
so n=1000*(2^6)=1000*64=64000 at 18:00 hrs.
next,
as above I'll represent exponents with ^ symbol
k^2*l*m^2*(-kn)^2
order of operations
1. parenthesis: well nothing to do here, "-kn" is reduced
2. next exponents
so the k is squared = k^2
the m (not the lm) is squared = m^2
and the -kn is squared --
(-kn)^2=(-k)^2 * n^2 = k^2 * n^2
3. so now comes the products (left to right)
giving us k^2 * l * m^2 * k^2 * n^2
grouping the k's gives us : k^4 * l * m^2 * n^2
or in spiffy notation :

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