SOLUTION: Please help me solve these equations: Simplify: (2X 2 yz 2)(X 2 y 2 z 2) 3= the numbers that are one space away are exponents. 2. (f/3) 3 3. (3/5) -2

Algebra ->  Exponents -> SOLUTION: Please help me solve these equations: Simplify: (2X 2 yz 2)(X 2 y 2 z 2) 3= the numbers that are one space away are exponents. 2. (f/3) 3 3. (3/5) -2      Log On


   

Question 23705: Please help me solve these equations: Simplify: (2X 2 yz 2)(X 2 y 2 z 2) 3=
the numbers that are one space away are exponents.
2. (f/3) 3
3. (3/5) -2
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
1. +%282x%5E2y%5E1z%5E2%29%2A%28x%5E2y%5E2z%5E2%29%5E3

When you raise a power to a power, you multiply the exponents. This should give you:
%282x%5E2y%5E1z%5E2%29%2A%28x%5E6y%5E6z%5E6%29

Now, when you multiply with the same base number you add exponents:
2+%2Ax%5E8%2A+y%5E7%2A+z%5E8+

2. %28f%2F3%29%5E3+ = %28f%5E3%29%2F%283%5E3%29 = %28f%5E3%29%2F27


3. %283%2F5%29%5E+-2

The negative exponent means to take the reciprocal of the fraction:
%283%2F5%29%5E+-2
%285%2F3%29%5E+2

Now, just square the numerator and square the denominator.
25%2F9

R^2 at SCC