SOLUTION: (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) e
Question 168709: (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate. Found 2 solutions by vleith, jim_thompson5910:Answer by vleith(2983) (Show Source): You can put this solution on YOUR website! See this --> http://mathforum.org/dr.math/faq/faq.number.to.0power.html
x^0 where x is anything except 0 is defined as 1
You can see that for all x!=0
this works for all x except x=0. If x=0 then term (0^y) in the denominator is undefined Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! ANY number (except 0) to the zeroth power is ALWAYS 1. So , , , , , , etc.
Now why did we exclude zero? It turns out that zero to ANY power (except 0) is 0. So , , , , , , etc.
So the question is: what is ??? Is is 1 (since the exponent is 0) or is it 0 (since the base is 0)? Since this contradiction occurs (and a few other reasons), this means that is an indeterminate expression.