SOLUTION: The expression goes as this: (3x^-4 y2)^-3 I need to write this WITHOUT negative exponents. Now I know how to get just so far, as in : x^

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Question 154476: The expression goes as this:
(3x^-4 y2)^-3
I need to write this WITHOUT negative exponents. Now I know how to get just so far, as in : x^–2" just means x2, but underneath, as in 1/(x2), yet I cannot come up with the necessary 'perfect' result. Can you please explain this to me and let me see what you've got as the correct answer to my inquiry? Thank so much.
once again: without negative exponents, I need to write: (3x^-4 y2)^-3
Answer by checkley77(12569) (Show Source):
You can put this solution on YOUR website!
(3x^-4 y2)^-3
Negative exponents places the terms in the denominator.
1/(3x^-4y^2)^3
Expand the terms using the exponent in the denominator.
1/(27x^-12y^6)
Now transfer the negative exponent to the numerator,
x^12/(27y^6)

SOLUTION: The expression goes as this: (3x^-4 y2)^-3 I need to write this WITHOUT negative exponents. Now I know how to get just so far, as in : x^–2" just means x2, but underneath, as