SOLUTION: I need to find z when z^6=64. I know the answer is 2 but what are the steps to solve for z?
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Question 151647This question is from textbook PreAlgebra
: I need to find z when z^6=64. I know the answer is 2 but what are the steps to solve for z?
This question is from textbook PreAlgebra
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Rewrite 64 as .
From here you can see that the answer is 2, but let's keep going
Take the 6th root of both sides. This will eliminate the exponent "6"
Take the 6th root of to get "z". Take the 6th root of to get 2
So the solution is
======================================
Here's another way to solve for "z"
Start with the given equation.
Subtract 64 from both sides.
Rewrite 64 as .
. Rewrite as . Rewrite as
Now let and
So we now have
Factor using the difference of squares formula
Plug in and
Factor the first binomial using the sum of cubes formula
Factor the second binomial using the sum of cubes formula
Rearrange the terms
Now set each factor equal to zero:
, , or
So our first two solutions are or
Now let's solve
Start with the given equation.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
Break up the fraction.
Reduce.
or Break up the expression.
So the next two solutions are are or
which approximate to or
-----------------------------------------------
Now let's solve
Start with the given equation.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
Break up the fraction.
Reduce.
or Break up the expression.
So the next two solutions are or
which approximate to or
========================================================
Answer:
So altogether, we have the 6 solutions
, , , , or
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