SOLUTION: A cup of tea cools exponentially according to the function T(x)=60(0.79)(^x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial tempe
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Question 126690: A cup of tea cools exponentially according to the function T(x)=60(0.79)(^x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial temperature of the tea? I think it is 90 degrees celcius. Can someone kindly confirm ???
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A cup of tea cools exponentially according to the function T(x)=60(0.79)^(x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial temperature of the tea? I think it is 90 degrees celcius. Can someone kindly confirm ???
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The "initial time" means x=0
If x=0 in your formula, T(0) = 60
That is the initial temperature.
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The initial temperature occurs when t=0
Start with the given equation
Plug in
Reduce the exponent to 0
Raise 0.79 to the zeroth power to get 1
Multiply
Add
So the initial temperature is 90 degrees. So you are correct.
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