SOLUTION: A sugar ant is approximately 2 × 10^−3 meters long. If you put 10 million sugar ants in a line, what is the distance from end to end?  200 meters  2,000 meters  20,

Question 1208239: A sugar ant is approximately 2 × 10^−3 meters long. If you put 10 million sugar
ants in a line, what is the distance from end to end?
 200 meters
 2,000 meters
 20,000 meters
 200,000 meters
Found 3 solutions by josgarithmetic, math_tutor2020, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
MULTIPLY!

---- and I'll let you finish that.
Answer by math_tutor2020(3816)   (Show Source): You can put this solution on YOUR website!

Answer: 20,000 meters

Work Shown

10 million = 10*(1 million)
= 10*10^6
= 10^1*10^6
= 10^(1+6)
= 10^7
In short, 10 million = 10^7.
Or put another way, 10 million = 10,000,000 = 1 followed by 7 zeros. The exponent tells us how many zeros are tacked onto the 1.

a = 2*10^(-3) = length of one ant in meters
b = 10^7 = number of ants
c = a*b = total length, in meters, of that number of ants assuming no gaps or overlaps.
We also assume the ants form a straight line.

c = a*b
c = 2*10^(-3)*10^7
c = 2*10^(-3+7)
c = 2*10^(4)
c = 2*10,000
c = 20,000 meters

Notes:
I used the exponent rule a^b*a^c = a^(b+c).
20,000 meters = 20 kilometers
20 kilometers = 12.4274 miles approximately
20 kilometers = 6,5616.7979 feet approximately
2*10^(-3) meters = 0.002 meters = 2 mm

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

A sugar ant is approximately 2 × 10^−3 meters long. If you put 10 million sugar ants in a line, what is the distance from end to end?  200 meters  2,000 meters  20,000 meters  200,000 meters 2 x 10^{- 3} x 10,000,000 2 x 10^{- 3} x 10⁷ --- Converting 10,000,000 to EXPONENT with base 10 2 x 10^{(- 3 + 7)} ----- Adding EXPONENTS, when multiplying same base 2 x 10⁴ = 2 x 10,000 = 20,000 meters

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