SOLUTION: (2x-6)/21 divided by (5x-15)/12 i got (x-24)/(x-105) am i right or can i keep going?
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Question 119844: (2x-6)/21 divided by (5x-15)/12 i got (x-24)/(x-105) am i right or can i keep going?
Found 3 solutions by jim_thompson5910, ptaylor, josmiceli:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression
Multiply the first fraction by the reciprocal of the second
Factor to get
Factor to get
Factor to get
Factor to get
Combine the fractions
Combine the fractions
Cancel like terms
Multiply
So simplifies to
In other words,
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
(((2x-6)/21)/((5x-15)/12) multiply both the numerator and denominator by 12/(5x-15). This will make the denominator equal to 1 and thus get rid of the complex fraction.
((2x-6)/21)(12/(5x-15))/((5x-15)/12)(12/(5x-15)) and this equals
(12(2x-6))/(21(5x-15))/1 and this equals
24(x-3)/105(x-3)=24/105=8/35 check my work
Hope this helps---ptaylor
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
divide top and bottom by 3
answer
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