SOLUTION: (2x-6)/21 divided by (5x-15)/12 i got (x-24)/(x-105) am i right or can i keep going?

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Question 119844: (2x-6)/21 divided by (5x-15)/12 i got (x-24)/(x-105) am i right or can i keep going?
Found 3 solutions by jim_thompson5910, ptaylor, josmiceli:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given expression

Multiply the first fraction by the reciprocal of the second

Factor to get

Factor to get

Factor to get

Factor to get


Combine the fractions


Combine the fractions



Cancel like terms



Multiply



So simplifies to


In other words,

Answer by ptaylor(2198)   (Show Source): You can put this solution on YOUR website!
(((2x-6)/21)/((5x-15)/12) multiply both the numerator and denominator by 12/(5x-15). This will make the denominator equal to 1 and thus get rid of the complex fraction.
((2x-6)/21)(12/(5x-15))/((5x-15)/12)(12/(5x-15)) and this equals
(12(2x-6))/(21(5x-15))/1 and this equals
24(x-3)/105(x-3)=24/105=8/35 check my work

Hope this helps---ptaylor

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!


divide top and bottom by 3




answer

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