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There are 14! permutations (listings) of 14 items.
14! = 1*2*3*4*5*6*7*8*9*10*11*12*13*14 = 87178291200.
ANSWER. 87178291200 different listings are possible.
Any of 14 teams can be listed first.
Any of remaining 13 teams can be listed second.
and so on . . .
Solved and explained.
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This problem is on PERMUTATIONS.
On Permutations, see introductory lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Simple and simplest problems on permutations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.