SOLUTION: write the equation of the line that contains the point (5,-2) and is perpendicular to the line 5x-2y=3 Also, how do I send you a problem that contains exponents when all I have

Question 114686: write the equation of the line that contains the point (5,-2) and is perpendicular to the line 5x-2y=3
Also, how do I send you a problem that contains exponents when all I have is a standard keyboard?
-Jamie
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
write the equation of the line that contains the point (5,-2) and is perpendicular to the line: 5x-2y = 3:
:
Find the slope of the given equation, put it in the slope intercept form (y=mx+b):
5x -2y = 3
-2y = -5x + 3
We want y to be positive; multiply equation by -1
2y = +5x - 3
Divide equation by 2
y = x -
Use the decimal form
y = 2.5x - 1.5
:
The slope (m1) of this equation is +2.5
:
The relationship of the slope of perpendicular lines is m1*m2 = -1
:
We know m1 = +2.5, find m2 the slope of the perpendicular line
2.5*m2 = -1
m2 =
m2 = -.4 is the slope
:
Find the equation of the line using the point/slope equation: y - y1 = m(x - x1)
We have m = -.4; Given: x1 = 5; y1 = -2
y - (-2) = -.4(x - 5)
y + 2 = -.4x + 2
y = -.4x + 2 - 2
y = .4x is the line that is perpendicular to the 5x - 2y = 3
:
If you graph these you can see that this is true

Note that the perpendicular line (purple line) goes thru x=5; y=-2
:
:
One way you can write exponents is use the ^ ; (upper case 6)
for instance an equation can be written y = x^3 + 2x^2 + x + 10
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