SOLUTION: can you find by mod (100) the last two number of {{{2^100}}} and {{{2^2006}}}

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Question 113235: can you find by mod (100) the last two number of

and

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find by mod (100) the last two number of
2^100
= 2^(10^2)
= [2^10]^2
= [1024]^2
= 24^2 (mod 100)
= 576 (mod 100)
= 76 (mod 100)
====================
and
2^2006
2^100 = 76 (mod 100)
2^200 = 5776 = 76 (mod 100)
2^400 = 5776 (mod100) = 76 (mod 100)
2^800 = 2^1600 = 76 (mod 100)
----------
2^2006 = 2^1600*2^400*2^6 = 76*76*64 (mod 100)
= 76*64 mod 100
= 4864 mod 100
= 64 mod 100
================
Cheers,
Stan H.




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