SOLUTION: \left(\frac{3x}{2x^2y^2}\right)^{-1}\ \left(\frac{y^3}{2x}\right)^2

Question 1124601: \left(\frac{3x}{2x^2y^2}\right)^{-1}\ \left(\frac{y^3}{2x}\right)^2
Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
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