SOLUTION: Find a value of x such that: (3+4)(3²+4²)(3^4+4^4)(3^8+4^8)(3^16+4^16)(3^16+4^16)(3^32+4^32)=4^x-3^x

Algebra.Com
Question 1117072: Find a value of x such that:
(3+4)(3²+4²)(3^4+4^4)(3^8+4^8)(3^16+4^16)(3^16+4^16)(3^32+4^32)=4^x-3^x
Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
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If you multiply the left side by  (3-4),  // which is (-1), // you will get that the left side is


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If you then compare it with the right side, you will find that  x = 64.

Solved.


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