SOLUTION: Can somebody PLEASE check my work, It would be GREATLY appreciated (:! 1. Is the expression x^3*x^3*x^3 equivalent to x^(3*3*3)? No, because the first one is x^9 and the second i

SOLUTION: Can somebody PLEASE check my work, It would be GREATLY appreciated (:! 1. Is the expression x^3x^3x^3 equivalent to x^(333)? No, because the first one is x^9 and the second i

Question 1103779: Can somebody PLEASE check my work, It would be GREATLY appreciated (:!
1. Is the expression x^3*x^3*x^3 equivalent to x^(3*3*3)?
No, because the first one is x^9 and the second is x^27
2.Rewrite in simplest radical form 1/(x^(-3/6))
(√x)
3. Rewrite in simplest rational exponent form, (√x)*(4√x) or (the square root of x)*(the 4th root of x)
x^(3/4)
4. Rewrite in simplest radical form (x^(5/6))/(x^(1/6))
(6√x^4) or (the 6th root of x^4)
5.Which of the following are equivalent
A.(4√x^3)
B. 1/(x^-1)
C.(10√(x^5)*(x^4)*(x^2))
D.(x^(1/3)*x^(1/3)*x^(1/3))
B. and D because they both equal (x^1)
Found 2 solutions by Boreal, jim_thompson5910:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
All correct.
4. could also be x^(2/3) or the cube root of x^2.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
1. Correct. You add the exponents for x^3*x^3*x^3 while you multiply them in x^(3*3*3)

2. Correct. You should get 1/[ x^(-1/2) ] = x^(1/2) = sqrt(x) where "sqrt" is shorthand for "square root"

3. Correct. Converting to exponential notation and then adding the exponents gives x^(1/2+1/4) = x^(2/4+1/4) = x^(3/4)

4. Not correct. You forgot to reduce the fraction 4/6 to 2/3. The answer is (cube root of x^2)

5. This seems a bit strange. C is hard to decipher. Do you mean the 10th root of all of that? Or just the first portion? You are correct in saying that 1/(x^(-1)) and (x^(1/3)*x^(1/3)*x^(1/3)) are both equal to x^1.
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