SOLUTION: Show that a quick way to square a positive integer ending in five is to place twenty-five after the product of the number formed by the digits preceding the five and the next integ

Question 106191: Show that a quick way to square a positive integer ending in five is to place twenty-five after the product of the number formed by the digits preceding the five and the next integer. for example, 65(squared) = 4225 [6x7 (the next integer) =42, then tack on 25] and 125(squared) = 15,625 [12x13 (the next integer) = 156, then tack on 25].
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Expand the right hand side.

Distributive property.
Distributive property.
Distributive property.
Example:

RELATED QUESTIONS
One positive integer is twenty-five less than five times another integer. Their product... (answered by fractalier)

the sum of five and a number added to the product of twenty and the number... (answered by richwmiller)

if five times the square of a positive number is added to the product of 38 and a number, (answered by Boreal,stanbon,math_helper)

five times an integer plus three times the square of the integer is twenty two. Find the... (answered by CubeyThePenguin)

the difference between 48 and a positive integer is equal to five times the interger.... (answered by checkley77)

twenty three times a positive integer is more than its square by 63. find the... (answered by Fombitz)

Five times of a positive integer less than twice its square by 3.Find the integer. solve... (answered by fractalier)

WRITE THE SYMBOLS THAT DISCRIBE THE FOLLOWING SENTNCES AND SOLVE. twice the quantity... (answered by rfer)

a five digit even number product of one's place and hundreds place is six and the sum is... (answered by ankor@dixie-net.com)