SOLUTION: log12(x+1)+log12^x=1
Algebra.Com
Question 1040047: log12(x+1)+log12^x=1
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Assuming you mean
combine
The exponent equiv
x^2 + x = 12
A quadratic equation
x^2 + x - 12 = 0
Factors to
(x+4)(x-3) =
x = 3, only the positive solution will work here
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{{{12^(x-2)=20}}}
How do you find x?
I did
{{{ (x-2)log12=20}}}
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