SOLUTION: Could you help me with the equation {{{ (-27)^(2/3) }}}

SOLUTION: Could you help me with the equation {{{ (-27)^(2/3) }}}

Algebra.Com

Question 103881: Could you help me with the equation

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
-27^(2/3)
cubert-27^2
cubert729
cubert(3*3*3*3*3*3)
cubert(9*9*9)=9 answer.

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