SOLUTION: x^2-3>2x
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Question 1026268
:
x^2-3>2x
Answer by
kekegeter (97)
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x^2-2x-3>0
x^2-3x+x-3>0
x[x^2/x-3x/x]+(x-3)>0
x(x-3)+(x-3)>0
(x-3)(x+1)>0
x-3=0
x+1=0
x=3
x=3
x=-1
x<-1
-1
x>3
x^2-3>2x
(-2)^2-3>2(-2)
x<-1
x>3