SOLUTION: The length of a rectangle is 10ft longer than twice the width. If the perimeter is 110ft, find the length and width of the rectangle.

Question 1024673: The length of a rectangle is 10ft longer than twice the width. If the perimeter is 110ft, find the length and width of the rectangle.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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W=width; L=length=2W+10ft
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P=2(L+W)
110ft=2(L+W)
55ft=L+W
55ft=(2W+10ft)+W
55ft=3W+10ft
45ft=3W
15ft=W
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L=2W+10ft=2(15ft)+10ft=30ft+10ft=40ft
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ANSWER: Length is 40 ft and width is 15 ft.
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CHECK:
P=2(L+W)
110ft=2(40ft + 15ft)
110ft=2(55ft)
110ft=110ft
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