# SOLUTION: (5x^-3 yz^2)^-2 please tell how to solve

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 Click here to see ALL problems on Exponents Question 681869: (5x^-3 yz^2)^-2 please tell how to solveFound 2 solutions by Edwin McCravy, MathLover1:Answer by Edwin McCravy(9717)   (Show Source): You can put this solution on YOUR website!``` Give the 5 and the y the exponent 1 so that every factor inside the parentheses will have an exponent showing: Now remove the parentheses by using the "exponential distributive" principle, i.e multiplying each exponent of each factor inside the parentheses by the exponent outside the parentheses on the right: 1 times -2 give -2, -3 times -2 gives +6, 1 times -2 gives -2, and 2 times -2 gives -4, and so far we have: Now since there are negative exponents, we must get all exponents positive. So we put a 1 denominator under that: Now we move the from the numerator to the denominator and change the sign of the -2 exponent to 2. Next we move the from the numerator to the denominator and change the sign of the -2 exponent to 2. Next we move the from the numerator to the denominator and change the sign of the -4 exponent to 4. Finally we eliminate the 1 factor and change the to 25 We could have done the last several steps in only one step, but I thought I'd break it down for you. Edwin``` Answer by MathLover1(7480)   (Show Source):