-> -> SOLUTION: (x^2/y^3)^-3
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Recall that (a^m)^n = a^(mn).
Then, (x^2/y^3)^-3 = (x^(2*-3) / y^(3*-3) = x^-6/y^-9
Remember that x^-n = 1/x^n
Then x^-6/y^-9 = y^9/x^6 <---- Answer