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Question 168709: (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate. : (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate.
Answer by vleith(1235)  (Show Source):
You can put this solution on YOUR website!See this --> http://mathforum.org/dr.math/faq/faq.number.to.0power.html
x^0 where x is anything except 0 is defined as 1
You can see that 
 for all x!=0
this works for all x except x=0. If x=0 then term (0^y) in the denominator is undefined
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Question 168709: (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate. : (a). Evaluate 6^,5^0,4^0,3^0,2^0,and 1^0. If you are defining 0^0 what value would you give for 0^0?
0^0 is inderterminate expression. Based on your observation in in part (a) explain why you think 0^0 is indeterminate.
Answer by jim_thompson5910(9897) (Show Source):
You can put this solution on YOUR website!ANY number (except 0) to the zeroth power is ALWAYS 1. So  ,  ,  ,  ,  ,  , etc.
Now why did we exclude zero? It turns out that zero to ANY power (except 0) is 0. So  ,  ,  , ,  ,  , etc.
So the question is: what is  ??? Is is 1 (since the exponent is 0) or is it 0 (since the base is 0)? Since this contradiction occurs (and a few other reasons), this means that is an indeterminate expression.
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