Questions on Algebra: Exponents and operations on exponents answered by real tutors!

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Question 175299: I have a story problem that consists of 2 parts. I can't even begin to figure out the first part so I definately cannot figure out the second. I was hoping there would be someone to help me out. Here is the problem:
The weight of an object follows this equation: w=Cr<-2> (the negative 2 is an exponent) where C is a constant, and the r is the distance that the object is from the center of the earth.
1. Solve the equation w=Cr<-2> for r.
2. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth)
Please help.
: I have a story problem that consists of 2 parts. I can't even begin to figure out the first part so I definately cannot figure out the second. I was hoping there would be someone to help me out. Here is the problem:
The weight of an object follows this equation: w=Cr<-2> (the negative 2 is an exponent) where C is a constant, and the r is the distance that the object is from the center of the earth.
1. Solve the equation w=Cr<-2> for r.
2. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth)
Please help.

Answer by ptaylor(1368) About Me  (Show Source):
You can put this solution on YOUR website!
(1)
w=Cr^(-2) or
w=C/r^2 multiply each side by r^2
wr^2=C divide each side by w
r^2=C/w take the square root of each side
r=sqrt(C/w)

(2)
3963=sqrt(C/100) or
3963=(sqrt(C))/10 multiply each side by 10
39630=sqrt(C) take square root of each side
C=199.07

Does this help??----ptaylor

Question 175571: (5x10(EXPONENT-8) x (3x10(EXPONENT14)) = 15x10(EXPONENT6) = 1.5X10(EXPONENT7)=15,000,000
(SORRY I DON'T KNOW HOW TO TYPE EXPONENTS)
MY QUESTION:
HOW DID THE PROBLE GET A DECIMAL PIONT (1.5) AND WHY HAS THE VALUE OF THE EXPONENT INCREASED BY ONE?
: (5x10(EXPONENT-8) x (3x10(EXPONENT14)) = 15x10(EXPONENT6) = 1.5X10(EXPONENT7)=15,000,000
(SORRY I DON'T KNOW HOW TO TYPE EXPONENTS)
MY QUESTION:
HOW DID THE PROBLE GET A DECIMAL PIONT (1.5) AND WHY HAS THE VALUE OF THE EXPONENT INCREASED BY ONE?

Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
You divide the 15 by 10 and you multiply the 10^6 by 10.
---------------------
You do this because scientific notation (ax10^b) requires that
0 So you can't just leave the answer as 15*10^6
--------------------------------
Cheers,
Stan H.

Question 175573This question is from textbook BARRONS ALGEBRA THE EASY WAY
:
8X10 (-9 exponent)
IS EQUAL TO 2X10 (-12 exponent) and is also EQUAL TO 0.000000000002
4X10 (3 exponent)
MY QUESTION:
I THOUGHT THAT DURING DIVISION I NEEDED TO SUBTRACT THE EXPONENT, IN THE EXAMPLE IT HAS ADDED IT, WHY? AND HOW DO I KNOW WHERE TO PUT THE DECIMAL POINT, AND WHERE THE DECIMAL POINT COME FROM?
This question is from textbook BARRONS ALGEBRA THE EASY WAY
:
8X10 (-9 exponent)
IS EQUAL TO 2X10 (-12 exponent) and is also EQUAL TO 0.000000000002
4X10 (3 exponent)
MY QUESTION:
I THOUGHT THAT DURING DIVISION I NEEDED TO SUBTRACT THE EXPONENT, IN THE EXAMPLE IT HAS ADDED IT, WHY? AND HOW DO I KNOW WHERE TO PUT THE DECIMAL POINT, AND WHERE THE DECIMAL POINT COME FROM?

Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
8X10 (-9 exponent)
IS EQUAL TO 2X10 (-12 exponent) and is also EQUAL TO 0.000000000002
4X10 (3 exponent)
---------------
Comment: Where do you get these numbers. What you post
as being equal are not equal.
---------------
8x10^-9 = 0.000000008
2x10^-12 = 0.000000000002
4x10^3 = 4000
======================
Cheers,
Stan H.

Question 175572This question is from textbook BARRONS ALGEBRA THE EASY WAY
: -11 6 -5 -4
(4X10 ) X (7X10 = 28X10 - 2.8X10 =0.00028
MY QUESTION:
-4
HOW HAS A DECIMAL PIONT GET (2.8) THERE AND WHY HAS THE EXPONENT (10 ) DECREASED?
This question is from textbook BARRONS ALGEBRA THE EASY WAY
: -11 6 -5 -4
(4X10 ) X (7X10 = 28X10 - 2.8X10 =0.00028
MY QUESTION:
-4
HOW HAS A DECIMAL PIONT GET (2.8) THERE AND WHY HAS THE EXPONENT (10 ) DECREASED?

Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
(4X10 ) X (7X10 = 28X10 - 2.8X10 =0.00028
?
-----------------------
(4X10) X (7X10)
= 28x10^2
Divide the 28 by 10 and multiply the 10^2 by 10.
= (2.8/10)x((7x10^2)x10)
= 2.8x10^3
===============
Cheers,
Stan H.

Question 175574This question is from textbook barrons algebra he easy way
: 6x10(4 exponent)
2x10(-5 exponent)
is equal to 3x10 (9 exponent)
and is equal to 3,000,000,000
my question:
why isn't the exponent a negative 9 on 3x10 (9 exponent)? and why are we not using a decimal point here like we would in example:
8x10 (-9 exponent)
4x10 (3 exponent)
is equal to 2x10(-12 exponent)
is equal to 0.000000000002
This question is from textbook barrons algebra he easy way
: 6x10(4 exponent)
2x10(-5 exponent)
is equal to 3x10 (9 exponent)
and is equal to 3,000,000,000
my question:
why isn't the exponent a negative 9 on 3x10 (9 exponent)? and why are we not using a decimal point here like we would in example:
8x10 (-9 exponent)
4x10 (3 exponent)
is equal to 2x10(-12 exponent)
is equal to 0.000000000002

Answer by Fombitz(1787) About Me  (Show Source):
You can put this solution on YOUR website!
Think about it.
You're dividing a large number (60000) by a much smaller number less than 1 (0.00002).
You will get an even larger number.
As an example:
2/(1/4)=8
.
.
.
Let's go through it step-by-step,
(6*10^4)/(2*10^(-5))=(6/2)*(10^4/10^(-5))
The rule of dividing exponential expressions is,
X^a/X^b=X^(a-b)
(6*10^4)/(2*10^(-5))=(6/2)*(10^4/10^(-5))
(6*10^4)/(2*10^(-5))=(3)*(10^(4-(-5))))
(6*10^4)/(2*10^(-5))=(3)*(10^(9))))
(6*10^4)/(2*10^(-5))=3*10^(9)
.
.
.
Similarly.
(8*10^(-9))/(4*10^3)=(8/4)*(10^(-9)/10^(3))
(8*10^(-9))/(4*10^3)=(2)*(10^(-9-3))
(8*10^(-9))/(4*10^3)=2*10^(-12)

Question 174985This question is from textbook McDougal Littell Pre Algebra
: Please answer the above question so we can check our answer while studying for finalsThis question is from textbook McDougal Littell Pre Algebra
: Please answer the above question so we can check our answer while studying for finals
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
I don't have the book, so I can't.

Question 174929This question is from textbook Mathmatics Application and Concepts
: 8+4-3This question is from textbook Mathmatics Application and Concepts
: 8+4-3
Answer by checkley75(3412) About Me  (Show Source):
You can put this solution on YOUR website!
8+4-3=12-3=9 ans.

Question 174802: What is the expression of a^3b^2 over a^2b: What is the expression of a^3b^2 over a^2b
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
What is the expression of a^3b^2 over a^2b
------------------
It's a^3b^2/a^2b
It can be reduced, a popular classroom activity.
Cancel a^2 and b
= ab



Question 174804: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?
Answer by ankor@dixie-net.com(4668) About Me  (Show Source):
You can put this solution on YOUR website!
what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?
:
The value for b which results in 0 in the denominator, to find that solve for b:
b^2 - 2b - 8 = 0
Factor
(b-4)(b+2) = 0
Two solutions
b = 4
b = -2
These are the illegal values for b, substitute these values for b in the denominator to see that we have division by 0 for these values
Question 174804: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?
Answer by Earlsdon(3816) About Me  (Show Source):
You can put this solution on YOUR website!
What are the "illegal" values of b in the fraction:
(2b^2+3b-10)/(b^2-2b-8)
The "illegal" (sometimes called "excluded") values of b are those values of b that would make the denominator equal zero. So, we set the denominator equal to zero and solve for b.
b^2-2b-8 = 0 Solve by factoring.
(b+2)(b-4) = 0 Apply the zero product rule.
b+2 = 0 or b-4 = 0, so that...
highlight(b = -2) or highlight(b = 4) These are the "illegal" values of b.

Question 174632This question is from textbook Strategies for Problem Solving
: I cannot find any formulas anywhere that suggest what I am looking for as a unit of measure. I need to get these right.
1. Identify the units on x in each of the following equations.
(a) (both y and z are measured in feet)
(b) (y is measured in inches)
(c) (t is measured in seconds)
(d) (both F and d are measured in meters)
I am really stuck on (c) and (d). Thanks
This question is from textbook Strategies for Problem Solving
: I cannot find any formulas anywhere that suggest what I am looking for as a unit of measure. I need to get these right.
1. Identify the units on x in each of the following equations.
(a) (both y and z are measured in feet)
(b) (y is measured in inches)
(c) (t is measured in seconds)
(d) (both F and d are measured in meters)
I am really stuck on (c) and (d). Thanks

Answer by Mathtut(1310) About Me  (Show Source):
You can put this solution on YOUR website!
we need the equations regarding x in order to answer these problems....please relist with the equations involving x.....thanks

Question 174580: (x^2-2x-3=0): (x^2-2x-3=0)
Answer by tutorcecilia(2020) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-2x-3=0
(x-3)(x+1)=0 [factor]
x-3=0 [set each factor equal to zero and solve for the x-value]
x=3
and
x+1=0
x=-1
So, the solutions are x = 3 and x = -1
Question 174580: (x^2-2x-3=0): (x^2-2x-3=0)
Answer by jim_thompson5910(9897) About Me  (Show Source):
You can put this solution on YOUR website!

x^2-2x-3=0 Start with the given equation.


Notice we have a quadratic equation in the form of ax^2+bx+c where a=1, b=-2, and c=-3


Let's use the quadratic formula to solve for x


x = (-b +- sqrt( b^2-4ac ))/(2a) Start with the quadratic formula


x = (-(-2) +- sqrt( (-2)^2-4(1)(-3) ))/(2(1)) Plug in a=1, b=-2, and c=-3


x = (2 +- sqrt( (-2)^2-4(1)(-3) ))/(2(1)) Negate -2 to get 2.


x = (2 +- sqrt( 4-4(1)(-3) ))/(2(1)) Square -2 to get 4.


x = (2 +- sqrt( 4--12 ))/(2(1)) Multiply 4(1)(-3) to get -12


x = (2 +- sqrt( 4+12 ))/(2(1)) Rewrite sqrt(4--12) as sqrt(4+12)


x = (2 +- sqrt( 16 ))/(2(1)) Add 4 to 12 to get 16


x = (2 +- sqrt( 16 ))/(2) Multiply 2 and 1 to get 2.


x = (2 +- 4)/(2) Take the square root of 16 to get 4.


x = (2 + 4)/(2) or x = (2 - 4)/(2) Break up the expression.


x = (6)/(2) or x =  (-2)/(2) Combine like terms.


x = 3 or x = -1 Simplify.


So the answers are x = 3 or x = -1


Question 174512: can you please simplify this problem for me? thanks in advance
3u^-4x^-9z^-5x^9*4u^-7*5z^8
: can you please simplify this problem for me? thanks in advance
3u^-4x^-9z^-5x^9*4u^-7*5z^8

Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
(3u^-4x^-9z^-5x^9)(4u^-7*5z^8)
(3x^9)/(u^4x^9z^5)(4*5z^8)/u^7
(3x^9)(20z^8)/(u^4x^9z^5)(u^7)
(60x^9z^8)/(u^11x^9z^5)
(60x^[9-9]z^[8-5])/u^11
(60x^0z^3)/u^11
60z^3/u^11 ans.

Question 174506: Solve the following equation for A : 2A/3 = 8 + 4A
A. -2.4
B. 2.4
C. 1.3
D. -1.3
E. 0
: Solve the following equation for A : 2A/3 = 8 + 4A
A. -2.4
B. 2.4
C. 1.3
D. -1.3
E. 0

Answer by tutorcecilia(2020) About Me  (Show Source):
You can put this solution on YOUR website!
2A/3 = 8 + 4A
(3) (2A/3) = 8 + 4A)) [eliminate the fraction by multiplying completely by "3"]
.
2A = 24 + 12A [Isolate the "A" term if possible]
.
2A - 12A = 24 [Simplify]
.
-10A = 24
.
(-10A/-10) = 24/-10))

.
A=-2.4

Question 173544: -7q^14x^u^14/11q^14x^12u^3: -7q^14x^u^14/11q^14x^12u^3
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
-7q^14x^[?]u^14/11q^14x^12u^3
HAVE YOU LEFT OUT A POWER TERM [ ] FOR X IN THE NUMERATOR?
IF YES. PLEASE RESUBMIT.

Question 174023: [(9n10)+(9n10)]n10 what is answer. Show work: [(9n10)+(9n10)]n10 what is answer. Show work
Answer by nycsub_teacher(90) About Me  (Show Source):
You can put this solution on YOUR website!
What does the n represent in this question?

Can you be more specific?

Question 174236: 1. Find the equation of the line that passes through the points (-4,-11)and (-2,-3).
2. find the slope of the line containing the given points. P1(3,11), P2(6,17)
Multiply
3. (x^2-7x+5)(3x-3)
4. 6x^10-3x^8+1/x^4
: 1. Find the equation of the line that passes through the points (-4,-11)and (-2,-3).
2. find the slope of the line containing the given points. P1(3,11), P2(6,17)
Multiply
3. (x^2-7x+5)(3x-3)
4. 6x^10-3x^8+1/x^4

Answer by Student3354(5) About Me  (Show Source):
You can put this solution on YOUR website!
1. Find the equation of the line that passes through the points (-4,-11)
and(-2,-3).
|x y 1|
|-4 -11 1| = 0
|-2 -3 1|
x*(-11+3) -y*(-4+2) + 12-22 = 0
-8x +2y = 10
4x - y = -5
---------------
2. find the slope of the line containing the given points. P1(3,11), P2(6,17)
slope, m, = (diff in y)/(diff in x)
m = (17-11)/(6-3)
m = 2
----------------
Multiply
3. (x^2-7x+5)(3x-3) = 3x^3 - 24x^2 +36x - 15
------------
4. 6x^10-3x^8+1/x^4 = 6x^6 - 3x^4 + 1/x^4

Question 174208: Simplify:
(matrix(5,1,<BR>
'',<BR>
4^(-3/2)x^(2/3)y^(-7/4),<BR>
'----------------------', '',<BR>
2^(3/2) x^(-1/3) y^(3/4)   ))^(2/3)
Thanks!
: Simplify:
(matrix(5,1,<BR>
'',<BR>
4^(-3/2)x^(2/3)y^(-7/4),<BR>
'----------------------', '',<BR>
2^(3/2) x^(-1/3) y^(3/4)   ))^(2/3)
Thanks!

Answer by Edwin McCravy(2190) About Me  (Show Source):
You can put this solution on YOUR website!

 
(matrix(5,1,
'',
4^(-3/2)x^(2/3)y^(-7/4),
'----------------------', '',
2^(3/2) x^(-1/3) y^(3/4)   ))^(2/3)

To remove the big parentheses, multiply
each of the six exponents inside the
parentheses, top and bottom, by the outer
exponent 2/3).

matrix(5,1,
'',
4^((-3/2)(2/3))x^((2/3)(2/3))y^((-7/4)(2/3)),
'----------------------------------', '',
2^((3/2)(2/3)) x^((-1/3)(2/3))y^((3/4)(2/3))   )

matrix(5,1,
'',
4^(-1)x^(4/9)y^(-7/6),
'-------------------', '',
2^(1) x^(-2/9)y^(1/2)   )

Move the factors with negative exponents in
the top to the bottom, changing the signs of
the negative exponents to positive. Also,
move the factors with negative exponents in
the bottom to the top, changing the signs of
the negative exponents to positive.

matrix(5,1,
'',
x^(4/9)x^(2/9),
'-------------------', '',
4^1* y^(7/6)2^1y^(1/2)   )

Add the exponents of x in the top 4/9+2/9=6/9=2/3
Add the exponents of y in the bottom 7/6+1/2=7/6+3/6=10/6=5/3
Write 4^1*2^1 as 4*2=8


matrix(5,1,
'',
x^(2/3),
'---------', '',
8 y^(5/3)   )

That may be acceptable as the final answer.

However we can rationalize the denominator by
multiplying top and bottom by y^(1/3)

matrix(5,1,
'',
x^(2/3)*y^(1/3),
'---------', '',
8 y^(5/3)*y^(1/3)   )

Write the factors in the top
as radicals. Add exponents on 
the bottom.

matrix(5,1,
'',
root(3,x^2)root(3,y),
'---------', '',
8 y^(6/3)   )

Multiply under the radicals
and simplify the exponent in the
bottom:

matrix(4,1,
'',
root(3,x^2y),
'-------', 
8 y^2   )


Edwin

Question 174145: Can you tell me if I am correct. If the problem is to simplify the following:
(4ab^2)^0 I believe that the answer is 1 because anything to the 0 power is 1. Am I correct?
: Can you tell me if I am correct. If the problem is to simplify the following:
(4ab^2)^0 I believe that the answer is 1 because anything to the 0 power is 1. Am I correct?

Answer by scott8148(2801) About Me  (Show Source):

Question 173827: Chapter 4 college math 117 algII
express using positive exponents and then simplify
3 with -2 being raised
: Chapter 4 college math 117 algII
express using positive exponents and then simplify
3 with -2 being raised

Answer by nycsub_teacher(90) About Me  (Show Source):
You can put this solution on YOUR website!
3^(-2) = 1/(3^2)
Since 3^2 = 9,the final answer is: 1/9

Question 173529: 2a to the negative 3rd power b to the 1st power if a= 2 and b= 12: 2a to the negative 3rd power b to the 1st power if a= 2 and b= 12
Answer by nycsub_teacher(90) About Me  (Show Source):
You can put this solution on YOUR website!
2a to the negative 3rd power b to the 1st power if a= 2 and b= 12
Do you mean 2a^(-3)(b^1)?
If so, here is the solution:
Replace a with 2 and b with 12
2(2)^(-3) (12^1))
2(1/8)(12)
(1/4)(12) = 3

Question 173527: 6z to the x power if x= -3 and z= 4: 6z to the x power if x= -3 and z= 4
Answer by jim_thompson5910(9897) About Me  (Show Source):

Question 173495This question is from textbook Strategies for problem solving workbook
: in an exponential expression such as A=be -(t/RC) power, we cannot attach units to the exponent -(t/RC) beacause a base, such as e can only be raised to a pure number. consequently, if the variable t in this equation is measured in seconds, what does this imply about the units on the product RC?This question is from textbook Strategies for problem solving workbook
: in an exponential expression such as A=be -(t/RC) power, we cannot attach units to the exponent -(t/RC) beacause a base, such as e can only be raised to a pure number. consequently, if the variable t in this equation is measured in seconds, what does this imply about the units on the product RC?
Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
in an exponential expression such as A=b*e^-(t/RC) power, we cannot attach units to the exponent -(t/RC) because a base, such as e, can only be raised to a pure number. consequently, if the variable t in this equation is measured in seconds, what does this imply about the units on the product RC?
---------------------------
RC must also be in seconds so the units cancel leaving t/RC a pure number.
========================
Cheers,
Stan H.

Question 173492This question is from textbook Strategies for problem solving workbook
: in the following equation, if x is measured in meters and t is measured in seconds, identify the units on the variable v
x=vt
This question is from textbook Strategies for problem solving workbook
: in the following equation, if x is measured in meters and t is measured in seconds, identify the units on the variable v
x=vt

Answer by solver91311(2177) About Me  (Show Source):
You can put this solution on YOUR website!
meters = (what?) * seconds?

meters per second means meters/second, so

meters=(meters/second)seconds. v must be measured in meters per second.

Question 172893This question is from textbook geometry
: How do you solve for y in the equation (y^2=y+30)?This question is from textbook geometry
: How do you solve for y in the equation (y^2=y+30)?
Answer by solver91311(2177) About Me  (Show Source):
You can put this solution on YOUR website!
The same way you would solve any quadratic.

First put it in standard form: y^2-y-30=0

Fortunately, this one factors because -6*5=30 and -6+5=-1, so

(y-6)(y+5)=0

y-6=0 => y=6
or
y+5=0 => y=-5
Question 172893This question is from textbook geometry
: How do you solve for y in the equation (y^2=y+30)?This question is from textbook geometry
: How do you solve for y in the equation (y^2=y+30)?
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve for y in the equation (y^2=y+30)?
------------
y^2=y+30 Get the zero on the right side
y^2 - y - 30 = 0
(y-6)*(y+5) = 0
One of the binomials has to be zero if the product is zero.
y = 6
y = -5

Question 172795: g^-5.g^8: g^-5.g^8
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
g^-5.g^8
IF THIS IS A MULTIPLICATION PROBLEM THEN:
G^8/G^5=G^3 ans.

Question 172688: y=-2x...find x?: y=-2x...find x?
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
y=-2x
-2x=y
x=y/-2 ans.

Question 172558: Need help on these that I have to complete today
Evaluate for a=3 and b= -4
1.a. (2b)^3
is the answer 512?
b. –ab^2(a- ab)
c. –a - b^2- 5
d. –2(ab)^2

2. Combine like terms
a. –5w+9x- 8w - 4x
b. –4+5y+ (-3) +5y+4y
I believe if I can have help with these I will be able to grasp the rest of my hw. Thank you anyone for your quick reply.
: Need help on these that I have to complete today
Evaluate for a=3 and b= -4
1.a. (2b)^3
is the answer 512?
b. –ab^2(a- ab)
c. –a - b^2- 5
d. –2(ab)^2

2. Combine like terms
a. –5w+9x- 8w - 4x
b. –4+5y+ (-3) +5y+4y
I believe if I can have help with these I will be able to grasp the rest of my hw. Thank you anyone for your quick reply.

Answer by Mathtut(1310) About Me  (Show Source):
You can put this solution on YOUR website!
1a...(2(-4))^3=(-8)^3=highlight(-512)
:
b....(-3)(-4)^2(3-(3)(-4))=(-3)(16)(15)=highlight(-720)
:
c....-(3)-(-4)^2-5=-3-16-5=highlight(-24)
:
d....-2((3)(-4))^2=-2(144)=highlight(-288)
:
2.a...-5w+9x-8w-4x.....so add the w terms and x terms together
........ highlight(-13w+5x)
b......-4+5y-3+5y+4y......combine y terms and constant terms
......highlight(-7+14y)
Question 172558: Need help on these that I have to complete today
Evaluate for a=3 and b= -4
1.a. (2b)^3
is the answer 512?
b. –ab^2(a- ab)
c. –a - b^2- 5
d. –2(ab)^2

2. Combine like terms
a. –5w+9x- 8w - 4x
b. –4+5y+ (-3) +5y+4y
I believe if I can have help with these I will be able to grasp the rest of my hw. Thank you anyone for your quick reply.
: Need help on these that I have to complete today
Evaluate for a=3 and b= -4
1.a. (2b)^3
is the answer 512?
b. –ab^2(a- ab)
c. –a - b^2- 5
d. –2(ab)^2

2. Combine like terms
a. –5w+9x- 8w - 4x
b. –4+5y+ (-3) +5y+4y
I believe if I can have help with these I will be able to grasp the rest of my hw. Thank you anyone for your quick reply.

Answer by Earlsdon(3816) About Me  (Show Source):
You can put this solution on YOUR website!
1. Evaluate for a = 3 and b = -4
a) (2b)^3 = (2(-4))^3=(-8)^3 = (-8)(-8)(-8) = highlight(-512)
b) -ab^2(a-ab) = -3(-4)^2(3-3(-4))=-3(16)(3-(-12)) = -48(15)=highlight(-720)
c) -a-b^2-5 = -3-(-4)^2-5=-3-16-5 = highlight(-24)
d) -2(ab)^2 = -2(3(-4))^2=-2(-12)^2 = -2(144)=highlight(-288)
2. Combine like-terms.
a) -5w+9x-8w-4x = -5w-8w+9x-4x=highlight(-13w+5x)
b) -4+5y+(-3)+5y+4y = -4+(-3)+5y+5y+4y=highlight(-7+14y)

Question 171847: 8r²=76r: 8r²=76r
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
8r²=76r
So? Do you have a question?

Question 170939: Sorry here is the question. I read it incorrectly.
How do you evaluate the expression
10^log(3.14)
: Sorry here is the question. I read it incorrectly.
How do you evaluate the expression
10^log(3.14)

Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
How do you evaluate the expression
10^log(3.14)
Let x = 10^log(3.14)
Take the log to get
log(x) = log(3.14)*log10
log(x) = log(3.14)
x = 3.14
===============
In general 10^log(a) = a
===============
Cheers,
Stan H.

Question 170810: rewrite the expression so that all exponents are positive
4d(to the negative 4) time e(to the negative 1) divided by f(to the -8)
: rewrite the expression so that all exponents are positive
4d(to the negative 4) time e(to the negative 1) divided by f(to the -8)

Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
rewrite the expression so that all exponents are positive
4d(to the negative 4) time e(to the negative 1) divided by f(to the -8)
------------------------------------
[4d^-4 * e^-1] / f^-8
= 4f^8 / [d^4*e]
======================
Cheers,
Stan H.

Question 170744: PLEASE HELP ME WITH THIS PROBLEM: y with the exponent 3 - 2y with the exponent 2 + 3y -4 when y = 5 i do not under stand if in the part 2y with the exponent 2 do i multiply 2 * 5 or do the exponent with 5 first?: PLEASE HELP ME WITH THIS PROBLEM: y with the exponent 3 - 2y with the exponent 2 + 3y -4 when y = 5 i do not under stand if in the part 2y with the exponent 2 do i multiply 2 * 5 or do the exponent with 5 first?
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
F(5)=Y^3-2Y^2+3Y-4
F(5)=5^3-2*5^2+3*5-4 [HERE YOU MUST FIRST RAISE TO THE POWER (5^2) THEN MULTIPLY
F(5)=125-2*25+15-4
F(5)=125-50+15-4
F(5)=86 ANS.

Question 170682: Find the ones digit of 7 raised to the 7th power raised to the 7th power. I multiplied 7, 14 times and I'm not sure that is correct. Thank you.: Find the ones digit of 7 raised to the 7th power raised to the 7th power. I multiplied 7, 14 times and I'm not sure that is correct. Thank you.
Answer by vleith(1235) About Me  (Show Source):
You can put this solution on YOUR website!
Let's write the equation
(7^7)^7
Using the power of powers rule, that yields
7^49
Now, 7*7 = 49
49*7 = 343
343*7 = 2401
2401 * 7 = 16807
Look at the ones digit above. You can see the pattern 7,9,3,1,7...
So the pattern repeats after each group of 4.
Thus 7^(4x+1) ends in 7
7^(4x+2) ends in 9
7^(4x+3) ends in 3
7^(4x+4) ends in 1
49/4 = 12.25 = (4*12) + 1
That means there are 12 groups of 4, plus one left over. That means you will be left with the ones digit ending in 7

Question 170644: 48a^3b^6c/12a^2b^4: 48a^3b^6c/12a^2b^4
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
48a^3b^6c/12a^2b^4
[48/12=4]
[a^3/a^2=a^(3-2)=a^1=a]
[b^6/b^4=b^(6-4)=b^2]
4ab^2c ans.

Question 170198: Simplfy (21x^-4y^-3)/(12x^4y^-2)
I came up with 7/(4x^8y) but am not sure if that is right
Thanks
: Simplfy (21x^-4y^-3)/(12x^4y^-2)
I came up with 7/(4x^8y) but am not sure if that is right
Thanks

Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
Looks OK to me.

Question 170231: 1. {3(7 - 9) + 16}^3 ÷ (-5) - 2^4: 1. {3(7 - 9) + 16}^3 ÷ (-5) - 2^4
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
{3(7 - 9) + 16}^3 ÷ (-5) - 2^4
= (3(-2 + 16)^3/((-5) - 16) \\\ It's not clear what's meant to be in the denominator. Use more parentheses.
= (3*14)^3/(-21)
= 42^3/(-21)
= 42*42^2/(-21) A shortcut
= -2*42^2
= -3528

Question 169577: (x^-3)^-2(x^-1y)^2/(xy^-2)^2: (x^-3)^-2(x^-1y)^2/(xy^-2)^2
Answer by stanbon(19705) About Me  (Show Source):
You can put this solution on YOUR website!
(x^-3)^-2(x^-1y)^2/(xy^-2)^2
=(x^6)(x^-2y^2) / (x^2y^-4)
= (x^4y^2)/(x^2/y^4)
= x^2y^6
====================
Cheers,
Stan H.

Question 169594: Simplify with positive exponents:
((a^3*b^(-2))^(-2)a^2b/(a^(-1)b))^(-2)
: Simplify with positive exponents:
((a^3*b^(-2))^(-2)a^2b/(a^(-1)b))^(-2)

Answer by Edwin McCravy(2190) About Me  (Show Source):
You can put this solution on YOUR website!

((a^3*b^(-2))^(-2)a^2b/(a^(-1)b))^(-2)

Put 1 exponents so everything will show an exponent:

((a^3*b^(-2))^(-2)a^2b^1/(a^(-1)b^1))^(-2)


First do this part: (a^3*b^(-2))^(-2)
(a^3*b^(-2))^(-2)= a^(3*(-2))*b^((-2)(-2))=a^(-6)b^4,
Then replace (a^3*b^(-2))^(-2) by a^(-6)b^4 

(a^(-6)b^4a^2b^1/(a^(-1)b^1))^(-2)

Inside the parentheses add exponents of a and of b:

((a^(-4)b^5)/(a^(-1)b^1))^(-2)

Now we're ready to remove the parentheses by multiplying
every inner exponent top and bottom by the outer
exponent -2:

(a^((-4)(-2))b^(5(-2)))/(a^((-1)(-2))b^(1(-2)))

(a^8b^(-10))/(a^2b^(-2))

Move b^(-10) from numerator to denominator and
change the sign of the exponent, and write b^10
on the bottom.
Likewise, move b^(-2) from denominator to numerator and
change the sign of the exponent, and write b^2
on the top. 

(a^8b^2)/(a^2b^10)

Subtract exponents, larger minus smaller, and place the
result in the numerator or denominator, depending on
which one had the larger exponent before.

So we subtract exponents of a, a^(8-2) or a^6
and place this on the top since the exponent 8 was
larger than the exponent 2 and a^8 was on the top.
We eliminate a^2 from the bottom:

(a^6b^2)/(b^10)

Finally we subtract exponents of b, b^(10-2) or b^8
and place this on the bottom since the exponent 10 was
larger than the exponent 2 and b^10 was on the bottom.
We eliminate b^2 from the top:

(a^6)/(b^8)

Edwin

Question 169630: The area of a rectangle is 15m^2 + 11m - 12. Find the length if the width is 5m-3: The area of a rectangle is 15m^2 + 11m - 12. Find the length if the width is 5m-3
Answer by gonzo(568) About Me  (Show Source):
You can put this solution on YOUR website!
area of a rectangle equals length * width.
let A = area
let L = length
let W = width
A = L*W
-----
you are given the area and the width.
you want to find the length
-----
A = L*W
divide both sides of equation by W:
A/W = L
which is the same as:
L = A/W
-----
A = 15m^2 + 11m - 12
W = 5m-3
-----
substitute for A and W:
L = (15m^2 + 11m - 12) / (5m-3)
-----
this is a straight long division problem:
first you figure how many times 5m will divide into 15m^2.
answer is:
3m ********* this is the first part of your answer.
then you multiply (5m-3) * 3m
answer is:
(15m^2 - 9m)
then you subtract (15m^2 - 9m) from (15m^2 + 11m - 12)
answer is:
(15m^2 + 11m - 12) - (15m^2 - 9m) =
15m^2 + 11m - 12 - 15m^2 + 9m =
(20m - 12)
-----
next you figure out how many times 5m goes into 20m.
answer is:
4 ********* this is the second part of your answer
then you multiply (5m-3) * 4
answer is:
(20m - 12)
then you subtract (20m-12) from (20m - 12)
answer is:
20m - 12 - (20m - 12) =
20m - 12 - 20m + 12 =
0
-----
your answer for (15m^2 + 11m - 12) / (5m-3) is (3m + 4)
(3m+4) is the length.
-----
to prove your answer is correct, go back to the original equation of:
A = L*W
substitute for A, L, and W:
15m^2 + 11m - 12 = (3m+4)*(5m-3)
(3m+4)*(5m-3) = 15m^2 - 9m + 20m - 12 =
15m^2 + 11m - 12.
this is the same as the area you started with so the equation is true proving that the value of (3m+4) for the length is good.
-----
your answer is:
length = (3m+4)
-----
Question 169630: The area of a rectangle is 15m^2 + 11m - 12. Find the length if the width is 5m-3: The area of a rectangle is 15m^2 + 11m - 12. Find the length if the width is 5m-3
Answer by checkley77(3848) About Me  (Show Source):
You can put this solution on YOUR website!
15m2+11m-12
(5m-3)(3m+4)
3m+4 is the length.

Question 169631: Divide - (x4-16) (x + 2): Divide - (x4-16) (x + 2)
Answer by Alan3354(1926) About Me  (Show Source):
You can put this solution on YOUR website!
Divide - (x4-16) (x + 2)
----------------
Do you mean Divide (x4-16) by (x + 2) ?
That's x^3 - 2x^2 + 4x - 8


Question 169632: simplify (x-2y8z)-5
---------
(x-4y9z)-4
Numbers are all exponents
: simplify (x-2y8z)-5
---------
(x-4y9z)-4
Numbers are all exponents

Answer by jim_thompson5910(9897) About Me  (Show Source):
You can put this solution on YOUR website!
Note:

(x^(-2)y^(8)z)^(-5)=1/(x^(-2)y^(8)z)^5


and


1/(x^(-4)y^(9)z)^(-4)=(x^(-4)y^(9)z)^(4)


In other words, we just flip the fractions


So

((x^(-2)y^(8)z)^(-5))/((x^(-4)y^(9)z)^(-4)) becomes



((x^(-4)y^(9)z)^(4))/((x^(-2)y^(8)z)^5)


(x^(-4*4)y^(9*4)z^(1*4))/(x^(-2*5)y^(8*5)z^(1*5)) Distribute the exponents.


(x^(-16)y^(36)z^(4))/(x^(-10)y^(40)z^(5)) Multiply the exponents.


x^(-16--10)y^(36-40)z^(4-5) Subtract the exponents


For example, (x^(-16))/(x^(-10))=x^(-16--10)


x^(-16+10)y^(36-40)z^(4-5) Simplify


x^(-6)y^(-4)z^(-1) Combine the exponents.


(1/x^(6))(1/y^(4))(1/z^(1)) Flip the variables with negative exponents.


1/(x^6y^4z^1) Combine the fractions.


1/(x^6y^4z) Simplify


==============================================

Answer:


So ((x^(-2)y^(8)z)^(-5))/((x^(-4)y^(9)z)^(-4)) simplifies to 1/(x^6y^4z)


In other words, ((x^(-2)y^(8)z)^(-5))/((x^(-4)y^(9)z)^(-4))=1/(x^6y^4z) where no variables can be equal to zero.