Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 32988: I am getting confused with negative signs. I've worked this problem several times but keep getting +3, but the answer is supposed to be 1/3. What am I doing wrong? Rebecca
-2x-4(x-2)=3x+5
I used distributive property for the -4, multiplying it by both the x and the -2. ??????
Click here to see answer by Earlsdon(6294) |
Question 32989: x^2/y^2-3x^2y^-2+4x^-3x^5y^-2-8y^-2/x^-2
I've tried this several times and keep getting -6x^2/y^2 but the answer is supposed to be -6x^2y^-2
Why does Saxon bring the y^2 up and make it a negative exponent?
Thank you for helping me understand this.
Rebecca
Click here to see answer by longjonsilver(2297)  |
Question 33229: 4)For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula, , let r = 10%, P = 1, and n = 1 and give the coordinates (t, A) for the points where t = 0, 1, 2, 3, 4.
a)Show coordinates in this space
Show work in this space
b)Show graph here
5)Logarithms:
a)Using a calculator, find log 10000 where log means log to the base of 10.
Answer:
b)Most calculators have 2 different logs on them: log, which is based 10, and ln, which is based e. In computer science, digital computers are based on the binary numbering system which means that there are only 2 numbers available to the computer, 0 and 1. When a computer scientist needs a logarithm, he/she needs a log to base 2 which is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:
Using this formula, find .
Answer:
Click here to see answer by venugopalramana(3286) |
Question 34605: I've worked this and get 89/36 but answer is supposed to be 71/36...???
Problem: -(-2)-(-2^-2)-[(-2)(3^-2)]
I get 2 +1/4 - (-2/9)
2 * 1/4 + 2/9
72/36 + 9/36 + 8/36 = 89/36
Where did I go wrong?
Rebecca
Click here to see answer by benni1013(197) |
Question 40282: Simplify and and answer with positive exponents only.
[(-12x^5y^-4)/(3x^-2y)]^-2
x to the power of 5, y to the power of negative 4, 3 to the power of negative 2, y to the power of one
everthing in brackets to the power of negative 2
Click here to see answer by stanbon(57984) |
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