# Questions on Algebra: Negative and Fractional exponents answered by real tutors!

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 Algebra: Negative and Fractional exponents Solvers Lessons Answers archive Quiz In Depth

 Question 415043: what how many 5s can go into 1/125 as an exponent Click here to see answer by stanbon(57307)

 Question 415237: use the product rule to simplify the expression. y*y^8*y^5= Can you show me how to do this, i dont understand it. Click here to see answer by solver91311(16877)
 Question 415237: use the product rule to simplify the expression. y*y^8*y^5= Can you show me how to do this, i dont understand it. Click here to see answer by josmiceli(9671)

 Question 415397: My teacher says you shouldn't have a negative exponent. What do I do to figure out a problem like this:(2b^4)^-1???? Click here to see answer by sudhanshu_kmr(1152)
 Question 415397: My teacher says you shouldn't have a negative exponent. What do I do to figure out a problem like this:(2b^4)^-1???? Click here to see answer by Edwin McCravy(8908)

 Question 415970: Multiply. I got to different answes for it. 1 was the other was..... which one is it? Click here to see answer by stanbon(57307)

 Question 416414: What is 9 over x to the negative 4th power equal Click here to see answer by MathLover1(6627)

 Question 416748: Need to solve by factoring: t^(5/3)-25t^(-1/3)=0 Book shows we take out t^(-1/3) and end up with t^(-1/3)[t^2-25]=0 Why do we take out the t^(-1/3)? Thanks!! Click here to see answer by lwsshak3(6494)

 Question 417003: How do I solve the following problem? (-5)-3exponent Click here to see answer by MathLover1(6627)

 Question 419964: the mass of a grain of salt is about 10 to the power of negative 4. about how many grains of salt in a box containing 100 grams of salt? Click here to see answer by ankor@dixie-net.com(15649)

 Question 419288: Please, help me solve this equation step by step so I can understand it. I have tried to simplify the 1/2 exponent on the left side to get rid of it, but it made the right side more complicated... I am confused on how to approach this equation. thanks! (x-2)^1/2=11*(x-2)^1/4-18 Click here to see answer by jsmallt9(3296)

 Question 421895: I can't quite understand where I am going wrong. -32a^-15b^10/-52a^13b^-14 I had answered it as 8b^4/13a^2 Wouldn't you change the places of the original exponents to make them positive and then subtract since you are dividing? The correct answer is 8b^24/13a^28. I cannot seem to grasp this idea of the negative exponents. I know you have to change the places to make them psoitive and that is what I had done. But it was marked wrong. This is the topic that is holding me back. Thank You Click here to see answer by ewatrrr(10682)
 Question 421895: I can't quite understand where I am going wrong. -32a^-15b^10/-52a^13b^-14 I had answered it as 8b^4/13a^2 Wouldn't you change the places of the original exponents to make them positive and then subtract since you are dividing? The correct answer is 8b^24/13a^28. I cannot seem to grasp this idea of the negative exponents. I know you have to change the places to make them psoitive and that is what I had done. But it was marked wrong. This is the topic that is holding me back. Thank You Click here to see answer by Theo(3458)

 Question 422520: ok i think i have the right answer but i'm not sure. i cancelled out the 4's and flip the reminding fraction so i can multipy it.. the answer is 2? 1 --- +4 c-1 __________ 2 --- -4 c-1 Click here to see answer by ewatrrr(10682)

 Question 423398: How do you solve for APR in this equation? 1.0593 = (1 + APR/3.3182)) ^3.3182 Click here to see answer by Theo(3458)

 Question 424775: How do you solve equation 2x^1/2 -3=0? (the one half is the exponent) Click here to see answer by stanbon(57307)

 Question 425701: 4x^-5 this needs to be solved to a positive exponet. I know it ends up as a fraction-could someone please explain the steps to getting to the answer. Thank you Click here to see answer by stanbon(57307)

 Question 427202: I need to graph these two linear equations x+y=9 and x-y=3 Click here to see answer by josmiceli(9671)

 Question 427789: I am working on exponents and have a couple of questions. 1) Solve -r^-2 if r=-3 I know the answer is -1/9 but I don't understand why it is a negative. I thought the negative symbol in the problem and the negative symbol on the 3 would cancel each other out and make it a positive. 2) What is the difference between the following three probs. I am just not understanding what to do about the - sign and when to do it! -5^-3 (-5)^-3 -(5)^3 I was not sure how to show the exponents and someone told me to use the ^ symbol so I did. Hope it makes sense. I am stuck!! Thank you. Click here to see answer by ankor@dixie-net.com(15649)

 Question 430116: Rewrite & simplify the given expression using positive exponents only. (square root x^-5 + x^-5y^7z^-2)(x^9y^-2z^9) Only x^-5 is a square root Click here to see answer by haileytucki(390)

 Question 430120: Expand & simplify. 5(3x-1) + 4(x^2 - 3x + 3)(x + 6) Click here to see answer by haileytucki(390)
 Question 430120: Expand & simplify. 5(3x-1) + 4(x^2 - 3x + 3)(x + 6) Click here to see answer by algebrahouse.com(1079)

 Question 430343: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)). ((x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2))) Remove the parentheses around the expression (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)). (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)) - I don't how this part works: Multiply ((x^(2)z^(2)~(x)+y^(7)))/(x^(5)z^(2)) by (x^(9)z^(9))/(y^(2)) to get (x^(4)z^(7)(x^(2)z^(2)~(x)+y^(7)))/(y^(2)). How do you get x^4z^7? Wouldn't you get x^11z^11????? HELP! Click here to see answer by richard1234(5390)

 Question 430356: Can someone confirm if I am doing this problem right? I have to provide the answer in fraction in lowest terms. Question: 2/(x-1) - 4/(x-1) My solution = 2(x-1)/(x-1)(x+1)- 4(x+1)/(x-1)(x+1) = -2x-6/(x+1)(x-1) Thanks Click here to see answer by stanbon(57307)
 Question 430356: Can someone confirm if I am doing this problem right? I have to provide the answer in fraction in lowest terms. Question: 2/(x-1) - 4/(x-1) My solution = 2(x-1)/(x-1)(x+1)- 4(x+1)/(x-1)(x+1) = -2x-6/(x+1)(x-1) Thanks Click here to see answer by Alan3354(30993)

 Question 430362: 2/(x+1) - 4/(x-1) Express as a fraction in lowest terms. Thanks Click here to see answer by stanbon(57307)