SOLUTION: If 10g of a radioactive substance are present initially and 3 years later only 5g remain, how much will be present after 7 years?

SOLUTION: If 10g of a radioactive substance are present initially and 3 years later only 5g remain, how much will be present after 7 years?

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Question 860765: If 10g of a radioactive substance are present initially and 3 years later only 5g remain, how much will be present after 7 years?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
10(x)^3 = 5
x^3 = 1/2
x = 0.793

10(0.793)^7 = 1.984 g
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