SOLUTION: Hello.. I need help with the following question to see if I have done it correctly. The question is as follows: "Simplify the following: 3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2

Question 855760: Hello..
I need help with the following question to see if I have done it correctly.
The question is as follows:
"Simplify the following:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1"
the / is obviously "divided by"..
My answer is written this way:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1
= 1/9 (x-1)^4 x^3 y^6 z^5 / 3x^3 y^4 (x-1)^-2 z^-1
= 1/9.3 (x-1)^4 (x-1)^2 x^3 x^-3 y^6 y^-4 z^5 z^1
= 1/3 (x-1)^6 x^0 y^2 z^6
= (x-1)^6 y^2 z^6 / 3
Can someone please let me know if I have done it correctly and if I haven't, can you please show me how to do it?
Thank-you very much,
zeedee
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Simplify the following:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1"
the / is obviously "divided by"..
My answer is written this way:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1
= 1/9 (x-1)^4 x^3 y^6 z^5 / 3x^3 y^4 (x-1)^-2 z^-1
= 1/9*3 (x-1)^4 (x-1)^2 x^3 x^-3 y^6 y^-4 z^5 z^1 -------------- Use * for multiply
= 1/3 (x-1)^6 x^0 y^2 z^6 ---------------- the 9*3 is in the DEN --> 1/27
= (x-1)^6 y^2 z^6 / 3
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