SOLUTION: there are 2. got them wrong on a test and cant come up with the teachers answer 1) solve for X: a/bx-c=0 . I get x=cb/a 2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squa

Question 729748: there are 2. got them wrong on a test and cant come up with the teachers answer
1) solve for X: a/bx-c=0 . I get x=cb/a
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1) solve for X: a/bx-c=0 . I get x=cb/a
Is it (a/b)x ?
Or a/(bx) ?
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9
Use ^ (Shift ^) for exponents.

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

1) solve for X:

........answer

2) ...if denominator same, just subtract numerators

.....factor denominator

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