SOLUTION: please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power. I know the answer is 1, but do not know how to get
to that an
Algebra.Com
Question 658689: please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power. I know the answer is 1, but do not know how to get
to that answer.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
(7^-4)^-2 = 7^(-4*-2) = 7^8
(7^4)^-2 = 7^(4*-2) = 7^-8
So "7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power" becomes
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