SOLUTION: http://m1146.photobucket.com/albumview/albums/pigrabbit_8/dfe0330c.jpg.html?o=0&newest=1 Please help with number 88. I'm confused on how I should deal with the negative exponent

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Question 647315: http://m1146.photobucket.com/albumview/albums/pigrabbit_8/dfe0330c.jpg.html?o=0&newest=1
Please help with number 88. I'm confused on how I should deal with the negative exponent. I know I have to switch it and put a 1 over but then the whole problem just became very, very confusing. I got 20x and I think the answer is wrong. Don't ask me how I got that, I probably skipped an important step or did something wrong. Thank you for your help.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

 ⇒ 

⇒ Note:5^(1/2)*5^(3/2) = 5^(1/2+3/2) & x^5/2/x^3/2 = x^(5/2-3/2)



 

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