SOLUTION: How do you solve 2^5/2 - 2^3/2? The fractions are fractional exponents (not mixed numbers). The answer is supposed to be 2^3/2 according to the answer key. I've seen this problem s
Algebra.Com
Question 637251: How do you solve 2^5/2 - 2^3/2? The fractions are fractional exponents (not mixed numbers). The answer is supposed to be 2^3/2 according to the answer key. I've seen this problem solved on this website elsewhere but for some reason the experts keep treating these fractions as mixed numbers. Please treat the fractions as exponents. Thank you!
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
2^5/2 - 2^3/2
----------------
=
=
=
=
=
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
as you can see, the is not a solution , and it could not be because you are subtracting that from
RELATED QUESTIONS
How do you solve 2^(5/2) - 2^(3/2)? The fractions are fractional exponents (not mixed... (answered by ewatrrr,josmiceli)
How do you subract with fractional exponents? 2 5/2 - 2... (answered by ewatrrr)
Please help me solve this equation. A step-by-step analysis would be extremely helpful as (answered by Alan3354)
Rational exponents: Negative exponents and fractional bases
What is the answer without... (answered by rapaljer)
(8^2/3*27^3/2)/(16^3/4*9^3/4) the 2/3 etc are fractional exponents (indices) not actual... (answered by oberobic)
How do you solve 2 (5/2) - 2 (3/2) the parentheses being fractions (answered by ExplanationCentral)
How do you factor this when the exponents are fractions, 12x^(1/2)(5x+2) + 5x^(3/2)(6)
(answered by rothauserc)
please help me find the answer. I can do the basic distributive property problems, but... (answered by Fombitz,vleith)
What would (3x^(2/5))*(2x^(1/2)) be?
I understand how to multiply fractional exponents... (answered by Alan3354)