SOLUTION: help would be appreciated
solve
-5 - 3^2 - 3(x - 2) = 3[(x - 2)3-4]
Algebra.Com
Question 62645This question is from textbook An Incremental Development
: help would be appreciated
solve
-5 - 3^2 - 3(x - 2) = 3[(x - 2)3-4]
This question is from textbook An Incremental Development
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
-5 - 3^2 - 3(x - 2) = 3[(x - 2)3-4]
= -5-9-3x+6=3[3x-6-4]
= -8-3x = 9x+30
12x=-38
x=-19/6
cheers,
Stan H.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
-5-3^2-3(x-2)=3[(x-2)3-4]
-5+9-3x+6=3[(x-2)-1]
10-3x=3[-x+2]
10-3x=-3x-3
10=-3
--------------------------
are you sure you coppied the problem correctly??????
RELATED QUESTIONS
(x - 2/3)^2 = 14
help to solve would be appreciated
thank... (answered by stanbon)
These problems have me stumped, any help would be greatly appreciated!
1. solve for x: (answered by stanbon)
how do you solve for the unknown of x/3 -7/8 = 2/5(x + 15/4) any help would be greatly... (answered by bucky)
(9x+3)/(x^2-9) - (5)/(x-3) Any help with this problem would be appreciated.
(answered by scott8148)
Solve: ^4(x^2)*^5(x^3)
Answer will be one of the following:
^20(x^5)
^10(x)... (answered by stanbon)
((4/x^2-9) + (2/x-3)) / ((1/x+3) + (1/x-3))
any help would be appreciated to simplify... (answered by Alan3354)
State the domain and solve the equation.
(3/x^2 - 25) - (1/x+5) = 1/x-5
Help would (answered by ewatrrr)
Help would be appreciated
Simplify
-4^2 + (-2)^4 - 3^3 - absolute vale of -4 -... (answered by stanbon)
any help would be appreciated on both parts a and b
Solve the following equations... (answered by Earlsdon)