SOLUTION: 3 friends, each with some cash, redistribute as follows; Ami gives enough money to Jan & Toy to double the amount that each has. Jan then gives enough to Ami & Toy to double their

Question 53929: 3 friends, each with some cash, redistribute as follows; Ami gives enough money to Jan & Toy to double the amount that each has. Jan then gives enough to Ami &
Toy to double their amounts. Finally, Toy gives Ami & Jon enough to double their amounts. If Toy has $36 when they begin & $36 when they end, what is the total amount that all 3 friends have?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
3 friends, each with some cash, redistribute as follows; Ami gives enough money to Jan & Toy to double the amount that each has. Jan then gives enough to Ami &
Toy to double their amounts. Finally, Toy gives Ami & Jon enough to double their amounts. If Toy has $36 when they begin & $36 when they end, what is the total amount that all 3 friends have?
:
This one seems to be hanging around. I can't seem to come up with a neat equation that will solve this thing but I felt that all the values had to be multiples of 36. The results were interesting (I thought)
:
Originally: A = 144; J = 72; T = 36
A gives away = -108, J + 72: T + 36
--------------------------------------
Resulting in A = 36; J = 144; T = 72
J gives away A + 36; J -108; T + 72
------------------------------------
Resulting in A = 72; J = 36; T = 144
T gives away A + 72; J + 36; T -108
------------------------------------
Final amts: A =144; J = 72; T = 36
:
They started out with A=144, J=72, T=36 and end up with same amts>

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