SOLUTION: I am having problems with negative fractional exponents. Here's a problem Ive been working on. (8/27)^-2/3

Question 394827: I am having problems with negative fractional exponents. Here's a problem Ive been working on.
(8/27)^-2/3

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I am having problems with negative fractional exponents. Here's a problem Ive been working on.
(8/27)^-2/3
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That exponent tells you three things:
1. take the cube root
2. square
3. invert
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You may do these in any order.
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Note: Taking the root will give you a smaller number to work with
so I would do it first.
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= (2/3)^-2
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Note: Now either invert or square
Inverting you get (3/2)^2
Squaring you get 9/4
======================
Cheers,
Stan H.
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