SOLUTION: (3x'3y'2)'2/xy'3
Key:
'=exponent eg: 3x'3 is 3X to the third.
/= fraction eg: 3x/3= 3x over 3.
Algebra.Com
Question 389485: (3x'3y'2)'2/xy'3
Key:
'=exponent eg: 3x'3 is 3X to the third.
/= fraction eg: 3x/3= 3x over 3.
Answer by haileytucki(390) (Show Source): You can put this solution on YOUR website!
((3x^(3)y^(2))^(2))/(xy^(3))
Expand the exponent (2) to the expression.
(3^(2)x^(3*2)y^(2*2))/(xy^(3))
Multiply 3 by 2 to get 6.
(3^(2)x^(6)y^(2*2))/(xy^(3))
Multiply 2 by 2 to get 4.
(3^(2)x^(6)y^(4))/(xy^(3))
Squaring a number is the same as multiplying the number by itself (3*3). In this case, 3 squared is 9.
(9x^(6)y^(4))/(xy^(3))
Reduce the expression (9x^(6)y^(4))/(xy^(3)) by removing a factor of xy^(3) from the numerator and denominator.
9x^(5)y
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