SOLUTION: How do you solve the equation w^-2+3w^-1-28=0?
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Question 280758: How do you solve the equation w^-2+3w^-1-28=0?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
w^-2+3w^-1-28=0
multiply by w^2
-1*(28w^2+3w+1)=0
-1*(4w-1)*(7w+1)=0
w=-1/7
w=1/4
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